Cu(s) = Cu2+(aq) + 2e. E° = -0.34 V
2Ag+(aq) + 2e = 2 Ag(s). E°= 0.80 V
Net equation
Cu(s) + 2 Ag+(aq) = Cu2+(aq) + 2 Ag(s)
E° = ( -0.34 + 0.80 ) = 0.46 V
E(cell) = E°(cell) - (0.059/n) log ( Cu2+ / ( Ag+)^2)
= 0.46 - (0.059/2)*log ( 0.0155 / ( 2.50)^2)
= 0.537 V
If you have any questions please comment
If you satisfied with the solution please rate it thanks
Write the net cell equation for the electrochemical cell. Phases are optional. Do not include the...
Write the net cell equation for this electrochemical cell.
Phases are optional. Do not include the concentrations.
Co(s)∣∣Co2+(aq, 0.0155 M)‖‖Ag+(aq, 2.50 M)∣∣Ag(s)Co(s)|Co2+(aq,
0.0155 M)‖Ag+(aq, 2.50 M)|Ag(s)
net cell equation:
Co+2Ag+⟶Co2++2AgCo+2Ag+⟶Co2++2Ag
Calculate ?∘cellEcell∘, Δ?∘rxnΔGrxn∘, Δ?rxnΔGrxn, and ?cellEcell
at 25.0 ∘C25.0 ∘C, using standard potentials as needed
Calculate Ecell, AGixn , AGxn , and Ecell at 25.0 °C, using standard potentials as needed. AG x = -89.4 AGxn = -104 E cell = .54
Write the net cell equation.
Calculate the following values at 25.0 degrees C
For the following electrochemical cell Cu(s)|Cu2+(aq, 0.01 55 M)IAg+(aq, 2.50 M)|Ag(s) write the net cell equation. Phases are optional. Do not include the concentrations. Calculate the following values at 25.0 °C using standard potentials as needed. Number Number kJ/ mol cell Number Number k.J/ mol
For the following electrochemical cell Sn(s)|Sn?(aq, 0.0155 M)lAg (aq, 2.50 M)JAg(s) write the net cell equation. Phases are optional. Do not include the concentrations. Calculate the following values at 25.0 ℃ using standard potentials as needed Number Number kJ/ mol cell Number Number &Grin- kJ/ mol cell
Consider the following electrochemical cell shown below. Sn(s)|Sn2 (aq, 0.0155 M)lIAg (aq, 3.50 M)IAg(s) Based on this cell write the net cell equation. Phases are optional. Do not include the concentrations. Calculate the following values at 25 °C using standard potentials as needed. Number cell Number cell
An electrochemical cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). What species are produced at the electrodes under standard conditions? E° = +0.80 V Agt(aq) + e- → Ag(s) Cu2+(aq) + 2 e- → Cu(s) E° = +0.34 V O Ag(s) is formed at the cathode, and Cu(s) is formed at the anode. Ag(s) is formed at the cathode, and Cu2+ (aq) is formed at the anode. Cu(S) is formed...
For the following electrochemical cell: Co(s)/Co^2+(aq,0.0155M)//Ag^+(aq,2.50M)/Ag(s) Write the net equation:______________ Calculate the following values at 25 degrees celcius using the standard potentials: E standard cell ________V E cell _____________V
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2 pts) a. Use the standard half-cell potentials listed below to calculate the standard cell potential (Eºcell) for 3 Sn(s) + 2 Fe* (aq) - 3 Sn2+ (aq) + 2 Fe(s) Sn 2(aq) + 2 e -Sn (s) E = -0.14 V Fe3+ (aq) + 3 e Fe(s) E° = -0.036 V A) -0.176 V B)-0.104 V C) +0.104 V D) +0.176 V b. Write...
Using the information in the table:
Which combination of metals, if used to create an
electrochemical cell, would produce the largest voltage?
Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e + Cu2+(aq) + 2e → Cu(s) Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) E half-cell = 0.7628 V Eºhalf-cell =...