Given,
L = 26 m ; rho = 2.4 x 10^-8 ; r = 2 mm ; D = 4.6 cm ; l = 1.65 m
A)B = 1.6 x 10^-2 T
We know that
B = u0 N I/L
I = BL/u0 N
N = 1.65/2 x 3.14 x 0.023 =
I = 1.6 x 10^-2 x 1.65/(4 x 3.14 x 10^-7 x 11.42) = 1480.55 A
R = rho L/A
R = 2.4 x 10^-8 x 26/(3.14 x (2 x 10^-3)^2) = 0.049
V = IR = 1480.55 x 0.049 = 72.55 Volts
Hence, V = 72.55 V
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