Question

The figure below shows two very long straight wires (in cross section) that each carry a current of 4.86 A directly out of the page. Distance d1 = 6.00 m and distance d2 = 5.00 m, what is the magnitude of the net magnetic field at point P, which lies on a perpendicular bisector to the wires? Number Units In the figure, a long straight wire carries a current 22.8 A and a rectangular loop carries current 2 25.9 A. Take a -1.34 cm, b-9.16 cm, and L-38.7 cm. What is the magnitude of the net force on the loop due to i1? Number Units

Answer 1

The distance of point from wire is, r = squareroot = (3 m)^2 + (5 m)^2 = 5.83 m The angle at point p is tan theta = 3 m/5 m rightarrow theta = 30.96 The magnetic field due to infinite wire B = mu_0 i/2 phi r = (4 phi times 10^- 3 T. m/A)(3.55A)/2 phi (5.83 m) = 1.22 times 10^- 3 T From symmetry of the wires, the net magnetic field at point p is B_act = 2 B sin phi = 2(1.22 times 10^- 3 T) sin (90 - 30.96) = 2.09 times 10^- 3 T