What is the oxidation number of Mn in the following coordination compound?
Li[Mn(NH3)2Br4]
[MnCl6]Cl
Oxidation number is an indicator of the degree of oxidation (loss of electrons) of an atom in a chemical compound.
Li[Mn(NH3)2Br4]
Li = +1
Mn = x
NH3 = 0
Br = -1
as the compound is neutral, we get
(+1) + x + (0) + (-1 * 4) = 0
+1 + x - 4 = 0
-3 + x = 0
x = +3
so the oxidation number of Mn in Li[Mn(NH3)2Br4] = +3
b) [MnCl6]Cl
Mn = x
Cl = -1
as compund is neutral we get
x + (-1)*6 + (-1) = 0
x - 6 - 1 = 0
x - 7 = 0
x = +7
so the oxidation number of Mn in [MnCl6]Cl is +7
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