a gas has a volume of 2.84L at 1.0atm and 0 degrees Celsius. At what temperature does it have a volume of 7.5L at 520 mm Hg?
Pi = 1 atm
Vi = 2.84 L
Ti = 0 oC = (0+273) K = 273 K
Pf = 520 mm Hg
= 520/760 atm
= 0.684 atm
Vf = 7.5 L
Tf = ?
use:
Pi*Vi/Ti = Pf*Vf/Tf
1*2.84 / 273 = 0.684*7.5/Tf
Tf = 493 k
= (493 - 273) oC
= 220 oC
Answer: 220 oC
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