Question

10-11. A linear magnetron has the following parameters Vo 32 kV lo 60 A Anode voltage: Anode current: f 10 GHz Operating frequency: Bo = 0.01 wb/m2 Magnetic flux density: Hub thickness: h-3 cm Distance between anode and cathode: d - 6 cm Compute: a. The electron velocity at the hub surface b. The phase velocity for synchronism c. The Hartree anode voltage l wish to help me in solving this question this the reference book is Microwave Devices and Circuits Third Edition SAMUEL Y. LIAO Professor of Electrical Engineering California State University, Fresno sec 10

Answer 1

(a) The electron velocity at hub surface V_h = e/m B_0 h V_h = 1.76 times 10^11 times 0.01 times 0.03 = 52.8MV e = 1.6 times 10^-14C m = 3.11 times 10^-31 Kg e/m = specific charge = 1.76 times 10^11 c kg^-1 B_09 = 0.01 wb/m^2 h = 3cm = 0.03m d = 6cm = 0.06m (b) for synchronization the phase velocity, w/beta should be equal to electron velocity ie, phase velocity, w/beta = e/m B_0 h = 52.8MV (c) Hareree Anode volatage V_hA middot (w/beta) B_0 d - 1/2 9 (m/e) (w/beta)^2 = (52.8 times 10^6 times 0.01 times 0.06) - 91/2 times 1/1.76 times 10^11 times (52.8 times 10^6^2 = 31680 - 7920 = 23.76 KV