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ENV3006C HW#4 The following data provided to you. Calculate the BODS of the WW sample (mg/L)...
3. (6 pts) Raw wastewater with initial BOD5 = 265 mg/L is treated in Wastewater Treatment...
3. (6 pts) Raw wastewater with initial BOD5 = 265 mg/L is treated in Wastewater Treatment Plant (WWTP), which can remove 65% of initial BOD. Students were asked to run BODs tests on the treated wastewater AFTER treatment. They used standard 300 ml bottle a. Find the volume of treated wastewater that should be put in the bottle to make sure that DO after 5 days will be at least 2mg/L (assume initial DO = 9.2 mg/L; and the bottle...
Given the following BOD data: Time (days) Diluted sample DO (mg/l). 7.95 3.75 3.45 2.75 2.15...
Given the following BOD data: Time (days) Diluted sample DO (mg/l). 7.95 3.75 3.45 2.75 2.15 1.80 Blank seeded sample Do (mg/l) 8.15 8.1 8.05 8.0 7.95 7.9 Find the BOD at 5 days knowing that the diluted sample was diluted 100 times, i.e., P=1/100-volume wastewater/[volume of wastewater+dilution water (300 ml)).
4. A 20 mL wastewater sample was mixed with 280 mL deionized (DI) water in a...
4. A 20 mL wastewater sample was mixed with 280 mL deionized (DI) water in a standard BOD bottle. The 5- day BOD test provided an initial dissolved oxygen concentration (DO intial) = 9 mg/L and a final dissolved oxygen concentration (DO final) = 3.5 mg/L. The BOD experiment was carried out at 20°C and the BOD rate constant at 20°C is 0.22/day. a. Find the dilution factor (P) and BODs value at 20°CY b. Find the ultimate BOD of...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both,...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both, using laboratory DO data. a. For sample A, seeded BOD test was performed. The initial DO concentration in the BOD bottle, which was filled with 2 mL of sample and 298 mL of seeded dilution water, was 8.9 mg/L just after preparation. After an incubation period of five days, the final DO concentration was reported as 1.8 mg/L. Meanwhile, DO concentration in the seed...
While interning at a wastewater treatment plant, you conduct a seeded BOD5 test of the lant's...
While interning at a wastewater treatment plant, you conduct a seeded BOD5 test of the lant's effluent. For the experimental bottle, you insert 30 mL of test sample into the 300-mL ottle and fill the rest with seeded dilution water. You fill a blank bottle with seeded dilution ater. You measure the following dissolved oxygen (DO) concentrations at the start and end f the 5-day test: Bottle Initial DO (mg/L) Final DO (mg/L) Experimental 8.1 4.6 Blank 7.8 6.7 hat...
6) (10 points) The BODs of a wastewater sample is expected to range from 25 to...
6) (10 points) The BODs of a wastewater sample is expected to range from 25 to 200 mg/L. Three different dilutions are prepared to cover the range. The same procedure was used for each analysis and 300 ml BOD bottles are used for the BODs test. Please determine average BODs value with standard deviation Sample Volume Initial DO, mg/L Final DO, mg/L 5 mL 9.2 6.7 10 mL20 mL 9.0 1.5 8.9 4.5
Water with 1.0 mg/L methylene chloride + 0.01 mg/L tetrachloroethylene), 70 kg adult drinks 2L/day for...
Water with 1.0 mg/L methylene chloride + 0.01 mg/L tetrachloroethylene), 70 kg adult drinks 2L/day for 30 years. What is hazard index? RfD = 0.060 for methylene chloride, RfD = 0.010 for tetrachloride 1 0.512 2 0.029 3 0.483 4 0.00029 q2) A test bottle (Blank) containing just seeded dilution water has its DO level drop by 1.1 mg/L in a five-day test. A 300-mL BOD bottle filled with 30 mL of wastewater and the rest seeded dilution water (this...
Ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2 disolved ...
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2 disolved oxygen content was 7.8 mg/L initially. After 20 days, the dissolved oxygen ssolv content had dropped to 5.3 mg/L. What is the ultimate BOD, and remaining BOD? Which of the two BODs give better prediction of BODL, and why?
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2...
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted;...
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted; data are summarized in the table below. Ten mL of wastewater was added per 300 mL bottle to determine the dissolved oxygen demand of the aged, settled wastewater seed (test A). The seeded test bottles (test B) contained 2.5 mL of industrial wastewater and 1.2 mL of seed wastewater a) What is the five-day BOD in this industrial wastewater? What is the k-value using...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
3. (6 pts) Raw wastewater with initial BOD5 = 265 mg/L is treated in Wastewater Treatment Plant (WWTP), which can remove 65% of initial BOD. Students were asked to run BODs tests on the treated wastewater AFTER treatment. They used standard 300 ml bottle a. Find the volume of treated wastewater that should be put in the bottle to make sure that DO after 5 days will be at least 2mg/L (assume initial DO = 9.2 mg/L; and the bottle...
Given the following BOD data: Time (days) Diluted sample DO (mg/l). 7.95 3.75 3.45 2.75 2.15 1.80 Blank seeded sample Do (mg/l) 8.15 8.1 8.05 8.0 7.95 7.9 Find the BOD at 5 days knowing that the diluted sample was diluted 100 times, i.e., P=1/100-volume wastewater/[volume of wastewater+dilution water (300 ml)).
4. A 20 mL wastewater sample was mixed with 280 mL deionized (DI) water in a standard BOD bottle. The 5- day BOD test provided an initial dissolved oxygen concentration (DO intial) = 9 mg/L and a final dissolved oxygen concentration (DO final) = 3.5 mg/L. The BOD experiment was carried out at 20°C and the BOD rate constant at 20°C is 0.22/day. a. Find the dilution factor (P) and BODs value at 20°CY b. Find the ultimate BOD of...
While interning at a wastewater treatment plant, you conduct a seeded BOD5 test of the lant's effluent. For the experimental bottle, you insert 30 mL of test sample into the 300-mL ottle and fill the rest with seeded dilution water. You fill a blank bottle with seeded dilution ater. You measure the following dissolved oxygen (DO) concentrations at the start and end f the 5-day test: Bottle Initial DO (mg/L) Final DO (mg/L) Experimental 8.1 4.6 Blank 7.8 6.7 hat...
6) (10 points) The BODs of a wastewater sample is expected to range from 25 to 200 mg/L. Three different dilutions are prepared to cover the range. The same procedure was used for each analysis and 300 ml BOD bottles are used for the BODs test. Please determine average BODs value with standard deviation Sample Volume Initial DO, mg/L Final DO, mg/L 5 mL 9.2 6.7 10 mL20 mL 9.0 1.5 8.9 4.5
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2 disolved oxygen content was 7.8 mg/L initially. After 20 days, the dissolved oxygen ssolv content had dropped to 5.3 mg/L. What is the ultimate BOD, and remaining BOD? Which of the two BODs give better prediction of BODL, and why?
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2...
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted; data are summarized in the table below. Ten mL of wastewater was added per 300 mL bottle to determine the dissolved oxygen demand of the aged, settled wastewater seed (test A). The seeded test bottles (test B) contained 2.5 mL of industrial wastewater and 1.2 mL of seed wastewater a) What is the five-day BOD in this industrial wastewater? What is the k-value using...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
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