Question

using super postion

Problem 1 [40 Points: Consider the circuit below, use superposition principle to answer the following questions: (show your solution in details then write the final answer) 12 Ω 12Ω ί, 10V 10 Ω 40 Ω 4A

Answer 1

Sol? For a given ech Let lov alone and open Therofen ckt beceous, Circut 4A. 12 .: Total Renrotere in IX + 10 lov R= 10 =12+(101140) R=12+8=202

:13 Ř 10 -0.5 A 20 thenfor (it is . Current dirion Rille, lo 310 I'x = 40 40+10 x0.5A 40 so •xos = 0.4A .: I'x = 0.44 10 W4A HIY Assune 4A current only and shart clt lov. Theofer cit beams Here is and 400 are in paralled 1:12/140=9.2312 Therfor it becerus, By current division Rule, YE za x1-4A) 10+9.231 12 19.231 4A 9.231 T = -1.92 By supepositing theorem Ix = 16+ -0.4 -1.92 = -1.52 A Ix= -1.52 A

Current is negative as direction of current is lower side as per question. It can be verified by simulation as shown

XMM1 R1 R4 Multimeter-XMM1 120 120 -1.52 A 10 V 11 4 A > R3 400 22 dB R2 100 +O Set...

Note-please find me in comment box if you find any difficulty. As current direction is given therefore current is estimated. Good luck