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Image for The LC circuit shown above has a capacitance C 0.05 pF and inductance L - 420 mH. Suppose that at time t = 0

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Answer #1

I max= 0.075 A

Q max= CVmax= CImax*Z =C*Imax*[2?(L/C)] = 0.05*10-6 * 0.075*2*?(420 -3 /0.05*10-6) = 21.74 ?C

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