Question

000 o gecor second 50 kg 80 kg An upward force of 1000 N is exerted on the 80 kg floor for 10.0 seconds and then discontinued. If the system is initially traveling upward at 10.0 m/s, a) In which direction does the system accelerate? Explain. (10) 10 b) Draw the free-body diagram for each while the force is exerted. Make explicit where Newton's 3rd Law is applicable. (30) c) Graph displacement vs. time (10) A 1,000N d 51 d) el nolion nee ve or download

Answer 1

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ansita considering both the blocks as a combined system wet downward force is fo = (50+80x10=1300N Net upward forces fu=100ON so aufnet :1300 -1000 downward 1 (mitm) (50+80) a: 2.3 m/s2 downwards) son quooon 50 809 Here normal force and in action reaction pair (0) As the system has constant acceleration the displacement -time graph is: - asog st are : FBO of all three blocks ei s- 1 m3 do mig-Tirmia To-T2=mza . a=(m, -M3) g -winny mitmz+Mz Mithiztus T₂ =( Quis mitmine) a mitmetm3 For friction T: -7z+ f T it mig T2 = m39 mig = mag + Muzy [41 - 43 +แฟน ๆ State with senscanner .