Question

General Chemistry I CHEM-1030 Laboratory Experiment No. 8 Gases: Charle Law Data Page Approximate Bath Measured Bath Top of Air Column Bottom of Air Column Temperature Temperature Ruler Reading Ruler Reading 100 oC 5.50 cm 90 C 5,25cm 20cm 80 °C 70 °C 0,26 cm 60 "C 50 °C 40 C 30 250m 20 °C 3.95 cm 10 °C 30 °C 0 250 m.

Answer 1

100 50 " p -50 E -100 8 -150 250 300 Temp (oC)

According to this graph, volume of gas is zero at -210oC. this is the value of absolute zero.

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Boiling water bath is 101.5oC

Length of air column = 5.65

According to Charles law :

T1V2 = T2V1

T1= 101.5oC, T2 = 200oC, V1 = 5.65 , V2 = ?

V2 = 200oC* 5.65/ 101.5oC = 11.13cm