Question

Convert cross section into complete steel

Find normal stress at point of interest

Find shear stress at point of interest

Steel 11 Stee WOOD Es = 30

Not imcomplete. The bottom figure shows beam under loading. Upper figure shows cross section. So, shear and moment diagrams must be sketch first then you can proceed with normal & shear stresses.

Answer 1

& kip - kip-ft 5 kipoft 3 kipft I * R 3t 3e 3 3 2 2 4 Rs first calculate reactions at supports - RATRB = 8+ [3x4+ / 2X 4x2 ] = 24 kip Emg=0 >>-Rax8+8x575-|(5-3)4/2(12-5-413) – 374(12-8-47 =O RA= 1.29 Kip RB = 22.71 kip Shear & Bending moment diagrams Calculation of shear force VA= RA= 1.29 Kip Ve = 1.29; Vc, = 1.29-8=-6.71 kép Vos 1.29-82-6.71 kip V8 = -6.71; VB, = -6.71 +22.71-([[(5-3)(8-8)/4+3-3)(8-5)) + 3 (8-8)) = 16 kip VE=0 Calculation of Bending moment MA=0 Me= 129x3 = 3.88 kip-ft

= 1,29*&-&(-3)-52-34.67 kip.ft. Mgr 0 +16 SF. Doto B.MD -34.67 from the above diagrams Amar = -34.67 kipaft Vmax = 16 kip. & Hogging Top layers are in ) tension ş bottom layers are in compresion I- Section 4ft 4ft. Steel Isft steel o steel 095 Lift Step 4. 5ft Stee) LOOD > Transfermed boood into no 86=0.83 3t Steel nstoel = oft Ewood - 100 = 0.05 Esteel (no)

Calculate centroidal ancis and moment of Enestia. A, = 481.5 = 6 ft?; 4,= 1+4.5+ 1,5 = 6.25 ft A₂ = 4.5x1= 4.5 ft²; 42 = 1+ 415 = 3.25 ft Az = 0.3x1 = 0.34€2; 43-015 ft. ū - Ary, + A24,+A343 6x6.25+ 45*3.257 0:3X015 - At Azt Az ỹ = 4.84 ft. 6+ 4.5 +0.3 1 I = I,ta, ya at Iz+ A29 ² +12+ A2 4,2 . POT oibb - NA 1 - 1x 4x1.53+ 61.4,21 1- 12 .14.34 (o3x + b284,341 v v 12 Is 13.053+ 18.9702 + 5.675 = 37.698 +24 Calculation of stresses shear stress Normal stress To vieta rame - 34.67X0.667-03 37.698 - 0606 lb/ft? - Suporte psi = 16.14x1.5) (5) ** 37.698% 1 37.698X1 1 = 19099 Iblist? = 13.26 psi

Please rate the answer and comment if you have any doubts

Thank you