Question

IN ILLIULIOL JU_SUN/Lab%20Exams/CHEZ101%2... Submit Answer kJ/mol Tries 0/2 7. Consider the following reactions: A-B AH = 272 kJ C-B AH = 36 kJ What is AH for A C ? It is possible that your answer could be either positive or negative. If it is negative, you must include the "minus" sign. Enter your answer as a decimal number. k] Tries 0/2 Submit Answer 8. Consider the following reactions: A + 2B - C + D AH = -224 kJ F+ G- D AH - 96 kJ What is AH for E+G A ? It is possible that your answer could be either positive or negative. If it is negative, you must include the "minus sign. Enter your answer as a decimal number. Submit Answer Tries 0/2 9. For a fixed amount of a gas at constant temperature, which graph illustrate the correct relationship between pressure and volume? Incorrect

Answer 1

5. Cp = 40184 J/g °c Mass of solution = 2107 = Mass of water Ti = 29.6°C Tz = 57.6°C... Since, temperature suses it is an exothermic su achom. Lone will be ave as the cuaction Heat peoduced is exothermic. Heat peoduced = Mass of x CP X CTR-TD Waten - 210 X 40184 x (57.6-29667 = 24601092J :. Heal peoduced =- 246ol.q2 I. = F24060 KJ). Ams: - 2406ok J (Since answer is asked E impositive number omit the-ve). M+2HQ Mll2 + H₂ me mole of metal M=0.7 Heal produced --36905 = -3.69 kJ Since temperature increases according to the question , it is an exothermic ovaétion: Thus, Hear produced will be negabive. ::OH = Heat produced 3,69 Moleof metal (M). Dot = 1- 5.27 kJ/mol Answer

1. A B OH = 27'z kТ Дң= 56 kТ . . с Он сам со - - - Зо Коо toya (2) ОА В ДН - 12 и т. 6 В Уе ДН- - 26 Т -2evogimer o the given CHOM Ф +3 A+) » k + DH will be negative - А С . Дң - ) 12 - 26 – 256 LT А те " - ДН- 246 Т. бA+20 Ус+ о Лң - 22 чLT б) E +2 -> С+ Е Л ң - - 2 счет 6 ft G D AH = 96kJ Он b@я Е. +tr>A ? ② - 0 :- € +2B CAF н+25 c+) . --2.0ч-(-229) (-) :-) :-) (-) АФЧ - - 20Ч+2.2Ч o - ouT E A +22 - 2 2 »ф+e-d-p » EXDATE 4) ③ +9 : EAD AIF :. дн - по-чь Eth . spH = 1165 E + ф + + n > А4+f + р. Ganswer. > Eth A final Reaction-

9. Temperature a constant PV = nRT Gras equation. -> P = nRT > pat Ein, R, T are constant] ensembling guaph between Pusv