the element X has naturally occurring isotope. The
masses (amu) and % abundance of the isotopes are given below. the
average atomic mass of the element is ?
Isotope: 221X, 220X, 218 X
Abundance: 74.22, 12.78, 13.00
Mass: 220.9, 220.0, 218.1
the element X has naturally occurring isotope. The masses (amu) and % abundance of the isotopes...
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu
8. An element has two naturally occurring isotopes. Isotope 1 has a mass of 120.9038 amu and a relative abundance of 57.4%. Isotope 2 has a mass of 122.9042 amu. Find the atomic mass of this element and, by comparison to the periodic table, identify it.
1. An element has two naturally occurring isotopes. Isotope 1 has a mass of 120.9038 amu, and a relative abundance of 57.4%. Isotope 2 has a mass of 122.9042, and a relative abundance of 42.6%. Find the atomic mass of this element and identify it by name and symbol.
The table below shows the atomic masses of the two naturally occurring isotopes of rubidium. Isotope Atomic Mass (amu) 85Rb 84.912 87Rb 86.909 The average atomic mass of rubidium is 85.468 amu. What is the percent abundance of each isotope? 85Rb % 87Rb %
An element has three naturally occurring isotopes with masses as listed below. The average atomic mass of this element is 28.08 amu. Determine the two missing percent abundances.^28X 27.98 amu % abundance =^29X 28.98 amu % abundance = 4.68 %^30X 29.97 amu % abundance =
An unknown element (Element X) has three naturally occurring isotopes. Complete the table by filling in the missing percent abundance (2 decimal places). Then calculate the atomic mass of element X (1 decimal place) and determine its identity by filling in its atomic symbol (case sensitive). Isotope Abundance (%) Atomic Mass (amu) 23.985042 1 78.99 2 24.985837 10.00 3 25.982593 amu Atomic mass of element X (1 decimal place): Atomic symbol of element X:
The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu. The relative abundances of these three isotopes are 99.76, 0.03800, and 0.2000 percent, respectively. From these data calculate the average atomic mass of Oxygen (in amu).
1. An element, A, has 2 naturally occurring isotopes. Isotope-1 has a mass of 40.00 amu, and isotope-2 has a mass of 44.00 amu. If isotope-1 is 4 times more abundant than the isotope-2, what is the mass of element A?
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 75% and 25%, respectively. Calculate its average atomic mass.