A sample of size n=96 is drawn from a normal population whose standard deviation is 5.7. The sample mean is 41.68. Construct a 99.9% confidence interval for m.
Standard error of the mean = SEM = S/?N = 0.582
t(?, N-1) = 3.396
Confidence interval = m +/- (t(?, N-1)*SEM)
Mean = 41.68
Lower bound: 39.7
Upper bound: 43.66
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