Using Kirchhoff's rules, calculate the current in R1 with the directions indicated in the figure below. Assume that R1 = 1.00 kohm, R2 = 3.00 kohm, R3 = 5.00 kohm, E1 = 75.0 V, E2 = 60.0 V and E3= 90.0 V.
Calculate the current in R2.
Calculate the current in R3
Find the magnitude of the potential difference between points c and f.
Here, the easy way to do this is node analysis because there is
only one node at c or b because they are the same voltage. Call
that voltage V. Let f be ground.
(V-75)/1k + (V-60)/3k + (V-90)/5k = 0
Multiply the equation by 1k
V(1 +1/3 + 1/5) = 75 + 60/3 + 90/5
V = (75 + 20 + 18)/(1 + 1/3 + 1/5) = 113/1.53 = 73.86 V = Vcf
<-----------
i1 = (73.86-75)/1k = -1.14 mA <--------------
i2 = (73.86 - 60)/3k = 4.62 mA <--------------
i3 = (73.86-90)/5k = -3.23 mA <-------------
Here the negative sign shown that the directions of i1 and i3 are
opposite of what we assumed initially.
Using Kirchhoff's rules, calculate the current in R1 with the directions indicated in the figure below....
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