Question

Problem 15.83 Part A The 12-lb collar B is at rest, and when it is in the position shown the spring is unstretched. Another 1-1b collar A strikes it so that B slides 4 ft on the smooth rod before momentarily stopping. The coefficient of restitution between A and B is e = 0.4. (Figure 1) Determine the velocity of A just after impact measured to the left. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is directed to the left and negative value if the velocity is directed to the right. (VA)2 = Value Units Figure < 1 of 1 > Submit Request Answer Part B k = 20 lb/ft Determine the average force exerted between A and B during the impact if the impact occurs in 0.004 s. Express your answer to three significant figures and include the appropriate units. 3 ft P= Value Units Submit Request Answer

Answer 1

20 solution calculating final Stretch P2 = √32 +42-3 - eft By usor k energy, ¥ Jr = {kx2 222 (we') - 2012)2 ne = 14:65ft/ During collision MAVATM BVB = MAVA +more VA +O EVA' +12(14065) VA-VA' 87.909 175.8 32-2 And ezvé-VA - VAO 004 = 14.65-VA' VA' +0.4VA = 14.65 W solving & VA' = - 39.764 fys [m' 39.764 $(6) for Block & F(t) = me Cré-ve) FC0-004) – 2C14-65-0) 1F=1364.907 lb