here,
current , I = 33 A
dimaeter , d = 2.5 * 10^-3 m
radius , r = 1.25 * 10^-3 m
a)
the magnetic feild at the surface , B = u0 * I /(2 * pi * r)
B = 1.26 * 10^-6 * 33 /( 2 * pi * 1.25 * 10^-3)
B = 5.3 * 10^-3 T
b)
x = 0.5 * 10^-3 m
so , x' = r - x = 0.75 * 10^-3 m
using Ampere's circuital law
Iin = I* ( pi * x^2) /( pi * r^2)
Iin = 33 * ( 0.75 * 10^-3)^2 /( 1.25 * 10^-3)^2
Iin = 11.88 A
the magnetic feild inside the wire , B' = u0 * Iin /( 2 * pi * x)
B' = 1.26 * 10^-6 * 11.88 /( 2 * pi * 0.75 * 10^-3)
B' = 3.2 * 10^-3 T
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