Question

The Department of Transportation wishes to know if states with a larger percentage of urban population...

The Department of Transportation wishes to know if states with a larger percentage of urban population have higher automobile and pickup crash death rates. In addition, it wants to know if either, the average speed on rural roads, or the percentage of rural roads that are surfaced, are related to crash death rates. Use the data file below to conduct a multiple regression analysis.

1. ANOVA table. (Conduct an hypothesis test for overall regression model using the p-value and interpret the result, calculate and interpret the coefficient of determination.)

2. Regression output. (Conduct a hypothesis test for each coefficient using the p-value and interpret the result. State the 95% confidence interval for each coefficient in the model and interpret the interval.)

3. Update the multiple regression model. (State the variables and your reasoning for including them into you model.)

4. State the result of your analysis. This should include the updated ANOVA table and the updated regression table. (What is the explaining power of your regression?)

DeathRate PctUrbPop AvgSpRural PctSurf
0.209624 0.38321999 58.90000153 0.94404
0.230769 0.54711002 58.20000076 0.59767
0.203146 0.25593001 58.59999847 0.41539
0.185097 0.61374003 59.5 0.8328
0.13017 0.06938 59 0.64795
0.180638 0.18474001 55.5 0.64428
0.082581 0.0747 62.20000076 0.97966
0.131261 0.30088001 58.20000076 0.99794
0.144513 0.16197 59.90000153 0.60671
0.180491 0.43443 58.5 0.73756
0.123272 0.17836 55.20000076 0.95256
0.191646 0.83332998 56.79999924 0.52655
0.12413 0.18516999 58.29999924 0.94289
0.149746 0.34165999 58 0.96991
0.206921 0.63046998 56.90000153 0.94492
0.191667 0.56928003 57.70000076 0.74628
0.186836 0.53368998 60.20000076 0.9079
0.169821 0.36958 56.29999924 0.93895
0.13138 0.69098002 57.90000153 0.93363
0.065987 0.14443 56.79999924 0.99821
0.092739 0.03108 58.5 1
0.145772 0.18148001 59.5 0.84516
0.143769 0.368 58.40000153 0.90854
0.177977 0.73865998 61.29999924 0.97715
0.190147 0.36059001 59.29999924 0.94228
0.310992 0.75445998 58.90000153 0.5953
0.194948 0.55374998 58.5 0.81586
0.262712 0.19231001 59.70000076 0.30828
0.121921 0.50063002 57.09999847 0.80282
0.088504 0.07231 54.09999847 0.95492
0.341783 0.66131002 60.59999847 0.27209
0.077234 0.11321 57 0.95212
0.184157 0.54518002 58.90000153 0.89573
0.233282 0.87440002 59.29999924 0.66466
0.123801 0.19848999 57.09999847 0.98357
0.207531 0.39414999 56.70000076 0.61739
0.11792 0.1928 58.09999847 0.86295
0.056928 0.08565 56 0.94201
0.201705 0.51817 59 0.68717
0.235725 0.85545999 58.40000153 0.75764
0.213225 0.36893001 53.5 0.97616
0.190853 0.21827 60.09999847 0.70449
0.119701 0.2053 57.70000076 0.42227
0.086864 1 57.90000153 0.92715
0.142341 0.34096 59 0.97875
0.173938 0.28193 56.79999924 0.79592
0.206782 0.63129002 58.29999924 0.72651
0.13983 0.39667001 58.59999847 0.94195
0.550532 1 60.20000076 0.57907
0 0
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Answer #1

we enter the data in excel and then goto dat > data analysis tab and select regression

thRate PctUrbPop AvgSpRur PctSurf 09624 0.38321999 30769 0.54711002 03146 0.25593001 85097 0.61374003 13017 0.06938 80638 0.18474001 82581 31261 0.30088001 44513 80491 232720.17836 91646 0.83332998 12413 0.18516999 49746 0.34165999 06921 0.63046998 91667 0.56928003 868360.53368998 69821 13138 0.69098002 65987 0.14443 58.9 0.94404 Data Analysis 58.2 0.59767 Analysis Tools 58.6 0.41539Histogranm 59.50.8328Random Number Generation OK Moving Average 59 0.64795 Rank and Percentle 55.5 0.64428 62.2 0.97966 58.2 0.99794 t-Test: Two-Sample Assuming Unequal Variances 59.9 0.60671 ZTest: Two Sample for Means 58.5 0.73756 55.2 0.95256 56.8 0.52655 58.3 0.94289 t-Test: Paired Two Sample for Means t-Test: Two-Sample Assuming Equal Variances 0.0747 0.16197 0.43443 58 0.96991 56.9 0.94492 57.7 0.74628 60.2 0.9079 56.3 0.93895 57.9 0.93363 56.8 0.99821 0.36958

we see that from the anova table the value of p is 0.00000
which is less than 0.05 , hence the model is statistically signficant

also from the gression table we see that the p value of AvgSPrural is 0.3600 , which is not less than 0.05 , hence this variable is not significant and does not contirubte towards explaining the difference

we can drop this variables from the model now

we see that from the anova table the value of p is 0.00000
which is less than 0.05 , hence the model is statistically signficant

also from the gression table we see that the p value of of all the variables are less than 0.05 , hence all the variables are signficant for the model

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