Question

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2,300 employees at its Sam's Club warehouse unit. Approximately half of the layoffs will be hourly employees (The Wall Street Journal, January 25-26, 2014). Suppose the following data represent the percentage of hourly employees laid off for 15 Sam's Club stores. - 55 56 44 43 44 56 60 62 57 45 36 38 50 69 65 a. Compute the mean and median percentage of hourly employees being laid off at these stores. Mean Median b. Compute the first and third quartiles. First quartile Third quartile c. Compute the range and interquartile range. Range Interquartile range d. Compute the variance and standard deviation. Round your answers to four decimal places. Variance Standard deviation

Answer 1

Solution: x - R = x - 52 16 64 100 49 256 ΟΒση ΓΙ 13 Σx = 780 Σ (r - ) = 0 Σ (r-s)? = 1402

a)

Means - ΣΕ 55 - 56 - 44 +43-44 +56 + 60-62 +57-45-36 +38-50 + 69 + 65 - 15 - 52 Median : Observations in the ascending order are: 36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60. 62. 65, 69 Here, n = 15 is odd. M= value of ("7 )observation - value of (15 > 1 )* observation = value of 8ih observation - 55

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b) Quartile

Arranging Observations in the ascending order. We get : 36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69 Here, n = 15 0:-(**)" value of the observation - value of the observation = 4th value of the observation = 44 value of the observation - 16 )" value of the observation = 12th value of the observation - 60

c)

Range = Highest value - Lowest value

Range = 69 - 36

Range = 33

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Interquartile Range (IQR):

IQR = Q3 - Q1

IQR = 60 - 44

IQR = 16

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d)

(x - 1) Sample Variance 52 - - 11-1 = 100.1429 Sample Standard deviation S = - 100.1429 - 10.0071