Question

Problem 15.111

Tx = 1 ft = 4 fts (VA) - 5 ft/s

A box having a weight of 4 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA)1 = 5 ft/s while connected to the end of a rope. The rope is pulled inward with a constant speed of vr = 4 ft/s. Neglect friction and the size of the box. I JUST NEED HELP SOLVING FOR B

A: Determine the speed of the box at the instant rB = 1 ft. (ANSWER = 10.8 ft/s)

B: How much work is done after pulling in the rope from A to B?

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Answer #1

Q. Areses - TE MB=167- LMA=2ft - Vr = 4ft. ne =4 lb (VAL 25. fl sec ------ m=w (A7 Now, using conservation of angul momentumI The work done after bulling in the crope from A to B is WAB = + (W) Vo - ļ (w ca, & $9=322.4} 3 (4.) 010-08-? () Ised S X (please like thank you....

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