p = 0.3, n = 42
i) the mean of the sampling distribution of p_hat is mu_p is equal to p = 0.3
ii) The standard deviation of the sampling distribution of p_hat is sigma_p is given by (p*(1 - p) / n)^(1/2)
So, sigma_p = (0.3*0.7/42)^(1/2) = 0.07071068
iii) The shape of the sampling distribution of p_hat is approximately normal since n is large.
the answers of the (iii) part may be different from mine but they surely will be derivatives of my answers
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