Please show the initial round (i.e., round 0) when encrypt the following plaintext using AES: (I have shown each step, please fill in each form) Plaintext: 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F Key: 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01 Both plaintext and key are 16 bytes in hexadecimal. a) Original contents of state (hint: please transfer the plaintext block to state): b) Initial AddRoundKey: State ⨁ Key c) SubBytes d) ShiftRows MixColumns is NOT required.
Plaintext: 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
Key: 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01
a). Original contents of state
00 | 04 | 08 | 0C |
01 | 05 | 09 | 0D |
02 | 06 | 0A | 0E |
03 | 07 | 0B | 0F |
Key
01 | 01 | 01 | 01 |
01 | 01 | 01 | 01 |
01 | 01 | 01 | 01 |
01 | 01 | 01 | 01 |
b). Initial AddRoundKey: It is XOR of Original State and Key.
01 | 05 | 09 | 0D |
00 | 04 | 08 | 0C |
03 | 07 | 0B | 0F |
02 | 06 | 0A | 0E |
c). SubBytes: To perform sub bytes, we use predefined S-Box. First character become row and second become column.
7C | 6B | 01 | D7 |
63 | F2 | 30 | FE |
7B | C5 | 2B | 76 |
77 | 6F | 67 | AB |
d). ShiftRows: Here, we will do right shift.
In first row, we are not shifting.
In second row, we shift one place further.
In third row, we shift two place further.
In fourth row, we shift three place further.
7C | 6B | 01 | D7 |
F2 | 30 | FE | 63 |
2B | 76 | 7B | C5 |
AB | 77 | 6F | 67 |
Please show the initial round (i.e., round 0) when encrypt the following plaintext using AES: (I...
To gain understanding AES, this problem asks you to perform one round of the encryption process. Given the following plaintext and key: Plaintext= 00 01 02 03 04 05 06 07 08 09 0A 0A 0C 0D 0E 0F Key = 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01 01 a. Show the original contents of state, displayed as a 4 × 4 matrix. b. Show the value of state after initial AddRoundKey....
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