Option (D) would be correct.
The index of unsaturation of the given molecular formula is 1 it means it has one double bond in the structure.
IR spectrum shows it can not be a carboxylic group as there is no peak at around 3500-3050 cm-1 but it has one peak at around 1750cm-1 which suggests that it may be an ester group.
1H-NMR spectrum shows 5 signals.
1. 3.91(t,2H) - the hydrogens of that carbon which is attached to oxygen.
2. 1.89(s,3H) - the hydrogens of that carbon which is bonded to carbonyl carbon.
3. 1.45(quintet,2H) - the hydrogens of that carbon which is at the 2nd position from oxygen.
4. 1.23(sextet, 2H) - the hydrogens of that carbon which is at the 3rd postion from oxygen.
5. 0.78 (t, 3H) the hydrogens of the last carbon.
Hence option (D) would be correct.
organic chem help What is the structure of the compound (C6H12O2) which gives the following IR...
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