Answer:
Step 1: Explanation:
Molarity is defined to be the number of moles of solute divided by volume of solution in liters
Molarity = number of moles of solute / volume of solution ( in L )
Step 1: Calculate the moles of sodium hydroxide (NaOH)
Volume = 1.7 L
Molarity = 3.1 M = 3.1 mol / L [ unit : M = mol/L]
Since we know ,
molarity = moles of solute / volume of solution in L
=> moles of solute(NaOH) = molarity × volume of solution
moles of solute(NaOH) = 3.1 mol / L × 1.7 L = 5.27 mol
Step 3: Calculation of mass of sodium hydroxide(NaOH)
Now, convert moles to mass by using molar mass
molar mass of sodium hydroxide ( NaOH ) = 39.997 g/mol
we know, moles = mass / molar mass
=> mass = moles × molar mass
mass = 5.27 mol × 39.997 g /mol ≈ 210 g
hence, the total mass in grams of sodium hydroxide ≈ 210 g ---> option(A)
Calculate the grams needed to prepare 1.7 L of sodium hydroxide 3.1 M 210 g оооо...
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