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Solve. For a hyperbolic mirror the two foci are 44 cm apart. The distance of the vertex from one focus is 10 cm and from the
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Answer #1

lae - 44 ) ae= 44 = 22 440 Galeo •cae, o) +10 focus Verties focus K 34-> a=12 6? = (aege-a= 22-12 = 484–144 5340 9-ae)² = 10²

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