Question

1. Speed dating. Data set "Speed Dating" includes "attractiveness" ratings of male dates made by the female participants in speed dating session. The summary statistics are n = 199, = 6.19, s = 1.99 a) Use a 0.01 significance level to test the claim that the population mean of "attractiveness" ratings of male dates made by the female dates is less than 7.00. Hypotheses: Ho: HA: Test Statistic: X-H T = df = SE SE here a = p-value: Decision: Conclusion: b) Calculate a 99% confidence interval appropriate for the population mean of "attractiveness" ratings of male dates made by the female dates less than 7.00 C.I. = x + tdf.SE taf Interpretation:

Answer 1

5= 1.99 198 = 5 ووا کہ Given na 199 X = 6.19 d=0.01 9 claim : Population mean of "attractiveness" rating of male dates made by the female dates is less than 7.00 Hypothesis Ho: Population mean of "attractiveness" is 7 i.e (11=7) Hii population mean of "attractiveness" is less than 7.00 iecuc7) d.f s n-1 = 1991 SE = 1.99 5 5 = 0.1411 d = 0.01 Test Statistic 6.19-7 T= x - 1 --5-7406 SE 0.1411 P-value P(TS-1F call) PTS -15.74061) =P(T5-5-7406) = 0.0000 30 Decision here p-value =0 < 0-0.01 . Reject the null hypothesis conclusion : Population mean of "attractivene ss" rating of male dates made by the female dates is less than 7.00

b)

is 99.7. confidence interval X + tarist 6.19 + 2-3453 (0:1411) tdf = t2.01.198 = 2-3453 from statistical table 6.19 + 0.3309 (5.8591 , 6.5209 ) 99-1. confidence interval for population mean is 5.8591 < l< 6.5209 Interpretation : The poparcation mean of "attoactiveness" puting of male dates made by the female dates lies between 5.8591 to 6.5209 i-e less 7.00