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11. Below is some data about two students who took the same exams as weliras the class mean and standard deviation for these
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Answer #1

a) from the given table Anna's and Megan's averages for all languages are

Anna's average = (83+83)/2 = 83

Megan's average = (77+95)/2 = 86

Here Megan's all languages average is 86 which is greater than 84.

So Megan should qualify the language honors

b) Anna's standard deviation s1 = 0

And Megan's standard deviation s2 = 12.73

Anna has no variation in language scores .

Anna's coefficient of variation =( 0/83)*100 = 0

Megan's coefficient of variation (12.73/86)*100 = 14.80

Low coefficient of variation means good performance .

Here Anna has low coefficient of variation so Anna's overall performance is good.

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