Question
Please help
3. A charged pith balls, carrying charge q -20 nC, hangs at an angle 6 30° from the vertical when suspended on a thin insulat
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Concept: force on a negative charge is opposite to the field, use this to find the force on charge along vertical and horizontal direction and apply equilibrium conditions for the ball to form equations to find mass as shown below

-component of fie is negative χ-anoo. So uraon hegahve charge du· to fier, wi loe tousard positve x nea ahtve chargebe along***************************************************************************************************
Check the answer and let me know immediately if you find something wrong... I will rectify the mistakes asap if any

Add a comment
Know the answer?
Add Answer to:
Please help 3. A charged pith balls, carrying charge q -20 nC, hangs at an angle...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please Help: Question 1: You measured the force between two charged pith balls where the pith...

    Please Help: Question 1: You measured the force between two charged pith balls where the pith balls were of the same size and mass. Your assumption was that the charge on the balls was the same. Consider this change to that situation. Instead of identical pith balls, one has twice the charge of the other. Both pith balls hang from strings of length L. Assume the masses are the same and both pith balls hang at the same angle. Derive...

  • In the figure, a charged particle of mass m = 3.40 g and charge q =...

    In the figure, a charged particle of mass m = 3.40 g and charge q = 0.290 mu C is suspended in static equilibrium at the end of an insulating thread that hangs from a very long, charged, thin rod. The thread is L = 13.0 cm long and makes an angle of theta = 35.00 degree with the vertical. Determine the linear charge density of the rod.

  • 0%charge 4. Two charged pith balls are suspended on very light 120 cm strings. Each has...

    0%charge 4. Two charged pith balls are suspended on very light 120 cm strings. Each has a mass of 10.0 g. Assume the angle the threads make from the vertical is 10 and that the balls are in equilibrium. Draw a free-body diagram for one of the pith balls and clearly label all forces with magnitude and direction. Assuming the pith balls are equally charged, what is the charge on each ball? (This is not a qualitative prediction; a numerical...

  • two pith balls of mass m and charge Q Repeat with the other producer. Are the...

    two pith balls of mass m and charge Q Repeat with the other producer. Are the results similar? Two pith balls of mass m and charge Q are suspended by threads of length L and are separated by total angle 2theta. Draw a free-body diagram for each pith ball. Using Coulomb's Law for the electrical force of repulsion and the weight of each of the pith balls, show that the charge on each ball is Q = plusminus 2L sin...

  • Please show all work 4. Two charged pith balls are suspended on very light 120 cm...

    Please show all work 4. Two charged pith balls are suspended on very light 120 cm strings. Each has a mass of 10.0 g. Assume the angle the threads make from the vertical is θ = 10° and that the balls are in equilibrium. Draw a free-body diagram for one of the pith balls and clearly label all forces with magnitude and direction. Assuming the pith balls are equally charged, what is the charge on each ball? (This is not...

  • A pair of 2 g charged pith balls is suspended by a L= 20 cm long...

    A pair of 2 g charged pith balls is suspended by a L= 20 cm long string. If the string makes an angle of θ-15, with respect to the vertical, what is the net charge on the balls? 4.

  • Hanging ball. A small insulating ball of mass M and positive charge Q hangs down from...

    Hanging ball. A small insulating ball of mass M and positive charge Q hangs down from gravity from a massless thread of length L attached at one end to a charged vertical wall of infinite extent that has surface charge density σ. Calculate the angle θ of the thread to the vertical.

  • Two charged pith balls are suspended on very light 120 cm strings. Each has a mass...

    Two charged pith balls are suspended on very light 120 cm strings. Each has a mass of 10.0 g. Assume the angle the threads make from the vertical is 0 -10 and that the balls are in equilibrium. Draw a free-body diagram for one of the pith balls and clearly label all forces with magnitude and direction. Assuming the pith balls are equally charged, what is he charge on each ball? (This qualitative predicti obtained.) is is not a qualitative...

  • In red, are the answers, please show the work for each:) 1. Two particles with charges,...

    In red, are the answers, please show the work for each:) 1. Two particles with charges, q 3 x 106 C and q2 12 x 106 C, are located along the x-axis at positions with coordinates (0, 0) and (4, 0) m respectively. All distances are n meters. (a) At what point along the x-axis, other than infinity, should a third charge q3 5 x 10 C be placed such that the net electric force on it is zero? (b)...

  • (2) Charged pith balls hang from strings and repel each other as shown in the photograph....

    (2) Charged pith balls hang from strings and repel each other as shown in the photograph. Assume the pith balls have equal mass and equal negative electric charge. The mass of each pith ball is O grams. The length of one string is 6.0 cm + 0.2 cm. The half-opening angle is 10" +1 (a) Estimate the number of excess electrons on one pith ball, include an estimate of the uncertainty in that number. Suggestion: start by deriving a symbolic...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT