a 100W light bulb connected to a 12.0 V source experiences a voltage surge that produces 14.0V for a moment. By what percentage does its power output increase? Assume its resistance does not change.
let the resistance of bulb be R.
then power=voltage^2/R
so R=1.44 ohms
so when voltage=14 volts
power=14^2/R=136.11 W
so % increase=(136.11-100)/100=36.11%
P = V^2/R
P is propotional to V^2
(14/12)^2 x 100
136.11 %
increae = 136.11 -100 = 36.11 %
a 100W light bulb connected to a 12.0 V source experiences a voltage surge that produces...
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