Molar mass of sodium bicarbonate = 84 g/mol
Moles of NaHCO3 in 1.5 g = 1.5/84 = 0.0178 mol
Molar mass of citric acid = 192.124 g/mol
Moles of citric acid in 1.5 g = 1.5/192.124 = 0.0078 mol
2 moles of sodium bicarbonate react with 1 mole of citric acid.
0.0178 mol of sodium bicarbonate reacts with 0.0178/2 = 0.0089 mol of citric acid
Available citric acid is only 0.0078 mol
0.0078 mol of citric acid reacts with 0.0078*2 = 0.0156 moles of sodium bicarbonate.
Excess sodium bicarbonate = 0.0178-0.0156 = 0.0022 mol
Mass of 0.0022 mol of NaHCO3 = 0.0022*84 = 0.1848 g
Answer : 0.1848 g
#3 part C 1 15126791 HMAC-d3bl02tefddo615328d1bf182619cfbde10301 Hybrid Chem 1411 Sp 19 CAwe rement 15 Chap 2...
C HW 2-Part F-Ch 19 HW- part 2 Problem 19.34 Constants Part A Detemine the ouments I,I and I in (Figure 1). Assume the internal resistance of each bar Express your answers using two significant figures separated by commas. 11-.09,.11,.20 Erevious Ansmers Resuest Answe X Incorrect; Try Again: 3 attempts remaining | Part B Figure 1of1 What is the torminal votage of the 6.0.V battery? Express your answer to two significant figures and include the appropriate units 120 V 22...
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I, = 2 !3! Submit X Inco Part C Complete Provide Feedback area, and d, and d, are the perpendicular distances between the parallel axes. The parallel-axis theorem relates the moment of inertia of an area about an axis passing through the area's centroid to the moment of inertia of the area about a corresponding parallel axis. Part B - Moment of inertia of the composite area about the x axis The moment of inertia of the triangular shaped area...