Given data is:
Mean(u) | 42 |
x-bar | 44 |
n | 37 |
standard deviation | 2.9 |
alpha | 0.1 |
Using excelL<data<megastat<hypothesis test<mean vs hypothesized
Here is the output:
Hypothesis Test: Mean vs. Hypothesized Value | ||||
42.00 | hypothesized value | |||
44.00 | mean 1 | |||
2.90 | std. dev. | |||
0.48 | std. error | |||
37 | n | |||
4.195 | z | |||
1.36E-05 | p-value (one-tailed, upper) | |||
43.22 | confidence interval 90.% lower | |||
44.78 | confidence interval 90.% upper | |||
0.78 | margin of error |
Answer: Test statistic: 4.195
Reject H0. The mean number of calls is greater than 42 per week.
Since the p-value is less than alpha (0.1). We reject the null hypothesis(H0). There is sufficient evidence to prove that there is the mean number of calls is greater than 42per week.
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