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A first order linear equation in the form y' + pay = f() can be solved...
(1 point) A first order linear equation in the form y +p(x)y -f(x) can be solved by finding an integrating factor H(x)exp /p(x) dx (1) Given the equation xy + (1 + 4x) y-6xe_4x find (x)-| xeN4x) (2) Then find an explicit general solution with arbitrary constant C (3) Then solve the initial value problem with y(1)e
A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor u(x) = exp c) dx (1) Given the equation y 2xy = 10x find H(x) = (2) Then find an explicit general solution with arbitrary constant C у %3 (3) Then solve the initial value problem with y(0) = 3 A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor...
(1 point) A first order linear equation in the form y' + p(x) = f(x) can be solved by finding an integrating factor (1) exp(/ pla) de) (1) Given the equation ay' + (1 + 2x) y = 8e 22 find (x) (2) Then find an explicit general solution with arbitrary constant C (3) Then solve the initial value problem with y(1) - ?
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp ( (1) Given the equation y, +-= 7x4 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(1) = 2
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp (1) Given the equation y' + 2y = 2 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(0) 2
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor u(x) = expl (1) Given the equation xy' + (1 +4x) y = 10xe 4* find y(x) = (2) Then find an explicit general solution with arbitrary constant C. y = (3) Then solve the initial value problem with y(1) = e-4 y =
(1 point) A first order linear equation in the form y p(x)yf(x) can be solved by finding an integrating factor x)expp(x) dx (1) Given the equation y' +2y-8x find u(x) - (2) Then find an explicit general solution with arbitrary constant C. (3) Then solve the initial value problem with y(0) 2 y-
A first order linear equation in the form y′+p(x)y=f(x) y p x y f x can be solved by finding an integrating factor μ(x)=exp(∫p(x)dx) μ x exp p x d x (1) Given the equation y′+6y=4 y 6 y 4 find μ(x)= μ x (2) Then find an explicit general solution with arbitrary constant C C . y= y . (3) Then solve the initial value problem with y(0)=3 y 0 3 y= y .
An equation in the form with is called a Bernoulli equation and it can be solved using the substitution which transforms the Bernoulli equation into the following first order linear equation for : Given the Bernoulli equation we have so . We obtain the equation . Solving the resulting first order linear equation for we obtain the general solution (with arbitrary constant ) given by Then transforming back into the variables and and using the initial condition to find ....
Solve the equation (3x2y-dx + y - 4x®y-dy=0 An implicit solution in the form F(x,y)=Cis-C, where is an arbitrary constant, and (Type an expression using x and y as the variables ) by multiplying by the integrating factor