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I need help understanding this problem.  If it can be done on a Ti84 calculator, please show how that can be done as this will help me out the most. If not, please show work and explain. Thank you!

7. In a representative sample of 816 coffee growers from Country X 463 growers were certified to sell to organic coffee markets while 85 growers were transitioning to become organic certi ed n Country Y 71% of coffee growers are organic certified. Is there evidence to indicate hat fewer than 71% of the coffee growers in Country X are either organic certified or transitioning to become organic certified? State your conclusion so that there is only a 10% chance of making a Type I error What are the hypotheses for this test? 0 A. Ho: p < 0 71 Ha: p: 0.71 H p> 0.71 Ha: p#071 O B. Ho p#0.71 Ha: p<0.71 OD. Ho:p#0.71 He p-0.71 O F. Ho:p> 0.71 H2 ps 0.71 O C. Ho: p 0.71 O E. Ho: p 0.71 Calculate the value of the z-statistic for this test. Round to two decimal places as needed.) Calculate the p-value for this test. p-value- What is the conclusion of the test? Round to three decimal places as needed.) the null hypothesis because the p-value is (2) the the probability of making a Type I error. Therefore, there is (3) evidence to indicate that fewer than 71% of the coffee growers in Country X are either organic certified or transitioning to become organic certified. (1) OReject (2) O greater than (3) O sufficient O insufficient O Do not reject less than

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Answer #1

null Hypothesis: alternate Hypothesis: Ho: 0.710 Ha: 0.710 for 0.1 level with left tailed test , critical value of z= Decision rule: 1.282 reject Ho if test statisticz < -1.282 sample success sample size 463 816.0000 std error -Se 0.0159 sample proportion p 0.5674 test stat Z (p-p)/Se= 8.98 p value 0.0000

for hypothesis: option B is correct

test statsitic z=-8.98

p value =0.0000

reject /less then /sufficient

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