Question

show all steps please

. Find i, v and the energy stored in the capacitor and inductor under steady- state conditions 2 mH mm + 5 mA 30 k92 6 uF 20 k92 1 w

Answer 1

Sol":- Criven circuit 2mH + 6uF 5mA 20kn 3okon V now circuit that for know we dc a inductor behaves as short circuit and acts as capacitor open circuit in stedy state, Hence will we re draw the given circuit with inductor short circuit and capacitor circuit open tie 5 mm ict Bokn 2oku m Now from current division rule i (30k)(5mA) (30k + 20%) 3 mA Hence value of e = 3mA Any now ve is voltage across 2ok resistance

hence (20kn)*(3MA) V = (20kn) ts? V = Volts Ans کی Yo energy stored in capacitor capacitor is given as Ec ICV2. where c = capacitance voltage V across capacitor Mow putting values Ec IX 6X1056x (60)? 0.0108 Joules Hence energy stored in capacitor is Ec 0.0108 Joules Ans Again 9 Energy stored in inductor in given as EL = ILI where L = inductance current flowing through inductor EL = 2x103 -3x(3x10-3)? EL= gx109 Joules I tx 2 Немсе Energy stored in inductor is EL 9 n Joules Ang
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