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-1 where M is the modulus of the congruence. If there is more than one solution, enter the (1 point) Solve each of the follow

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Answer #1

(a) 1852 3 1 (mod 266) 185% = 1 (mod 266) (185-266)X = limod 266 -81.223 i (mod 266 ) -8121 = 1 +266 (mod 266) -81% = 267 (mo

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