since C2 and C3 are in parallel so resultant of C1 and C2
C23=C2+C3 =50u+10u
C23=60 uF here u=10^(-6)
now
C23 and C1 are in series
So
C(equivalent)= C1×C23/(C1+C23)
=40×60/(40+60)
C(equivalent)= 24 uF. Answer
O Time ゴNotes Evaluate D Feedback Print between points A and B in the following circuit...
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