What is the probability that a fair coin lands tails up ten times in a row?
Answer
This is a case of binomial distribution with n = 10 and p = 0.5 (because there is 1/2 or 0.5 probability of getting a tails)
using the binomial formula
P(x=r) = C(n,r)*p^r*(1-p)^{n-r)
setting n = 10, r = 10 and p = 0.5
we get
P(x=10) = C(10,10)*0.5^10*(1-0.5)^{10-10}
={10!/((10-10)!*10!}*0.5^10*0.5^0
= 1*0.5^10*1
= 0.00098
= 0.0010 (rounded to 4 decimals)
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