Question

Three lines are defined by the three equations: x + y = 0 x-y=0 2x+y=1 The three lines form a triangle with vertices at: O A.
THE CORRECT ANSWER IS: A y=-x y=x -2x + 1 y=-2x +1 intersection of y=x and y=-x is (0,0) intersection of y = x and y = -2x +
0 0
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- 2 Given three lines Exuations are x+y = 0 - 0 X-4 = 0 - ☺ 2x + y = 1 - 3 Solving , ④ weget __ from Eun ③ y=-2 put y=-x in 0- Now solving ② 0 , wesel From Epn . y .. . put y=-x in Eson ③ , weset 2(X) + (-x)=1 ) [x = 1] put aal in een , weget .......

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