Question

A body of mass, 0.5kg traveling in the positive direction of the x-axis with a speed of 10 m/s collides with another body of massz 0.75kg and traveling with a speed of 15 m/s in the negative direction of the x-axis. If after the collision the body of mass, moves with speed of 5 m/s in the negative direction of the x axis. Determine: a The velocity (magnitude and direction of the body mjafter the collision b. Indicate the type of collision (elastic or inelastic) and why! c. The impulse received by particle 2 d. If the collision lasted an interval of N = 5x105, determine the average force upon particle 2

Answer 1

Griven, mi= 0.5kg , vitlomis, vi m2 = 0.75kg i ve= - 15 m/s, V2 =- 5 mls. Pre vil and val are speed after collision @ vi=9 Use conservation of linear momentum before and after collision- mivit mave a movi & mara 0.5kg xiomis - (o 75 kg x 15m/s) = movi - (0.75 kg x 5 m/s) 5 kg m/ - 11.25 kgm/s = mivi- 3.75 legmle mivi = (5-11-25 +3.75) leg m/s mivi = -2.5 kg mis Ni = -2.5 mls = 5 ms. - - 0.5 Tvi= 5 m/s along negative direction! of naanis Ans

6 Collision is elastic because after collision both the masses mones independent nog and there is no loss of kinetic Energy. C Impulse by particle 2 Impulse = change in momentum (AP) I = (Pfinal - Pinitial) for mans 2 I = malve - v2) I = 0.75kg (5 - 15) m/s I = - 7.5 kg m/s Ang @ At = 5x10-3s taxcotola Force (F) = Impulse (I) 7.5kg mis 581035 F = 15oon Ane