Question

2) a) Consider the following molecule Given what you have learned about hybridization theory, draw an image or images explaining the bonding situation in this molecule. I want you to draw out all of the orbitals, hybrid orbitals and how they overlap to form the bonds in the molecule. Indicate the % sorp character in the given atomic and hybrid orbitals. Which CC bond or bonds are the longest? In a paragraph or so explain the image or images you just drew. Q Screen Shot 2020-03-15 at 5.58.26 PM Û Z O @ Q Search b) Lastly, consider the molecule below. Indicate the Molecular formula, the molar mass label the hybridization of each atom except for hydrogen, indicate any chiral centers with a which bond or bonds are the shortest identify by name of each functional group with an arrow pointing to the group

Answer 1

2003 си I . - - ® ,@@ carbon ip forming ☺ four bond of single type bond ire Sigma bond. 4 Sigma bond > Sps Hybridization O Carbon is forming 3 sigma band and I pi-bond (overlapping of 1 pure p-orbital) 13- Sigma bond > Spa Hybridization) l Spa Hybrid oskaita, Sp3 Hybrid Orsifal . Spaz sp3 Ofe gel 0 2602 H 3 sp2 Hybrid ootital Px Py P 1.7 4.883 Hybridorbital erlapping 100% .(s)-Character as sp3 Hybrid Head-on overlappin PIW 3 spsy 3 orbital ) 11 Headon overlapping between Goo bital H and sp3 Huboid orbital sp2 63 942 ( Sielewise Head on overlapping Sp b/w CQ3 up? Hybrid orbita H-bonding overlapping Head on overlapping b/w sp2 orbital of Sorbital

– sp2 – ol s character - 33.33%. 7. p. character - 66.66% Sp3 ps-charracher - 25t. A so p-character - 75% o f longest bond: - c c bond with sp3-sp3 Hybrid orbital- - In Criven Molecules there are four types of sigma bond and one type of 1-bond. four types i Sigma bond- (sp 3-Sp3, 4p3 sp2 & sp3 sq p?s). Sigma bond formed by Head on overlapping. Side will overlapping of prorbital of Carbon - carbon will produce -bond.

C CH HSCH Molecular formula;- (10 H iz Os Molar Massas > 10x12 + 12x1.00% + 2x16 + 32.065 120+ 12:096+32+32.065 = .1960166 g/mol . Molar Mass= 196 261 g/mol) HS -CH2 1 Centre (=c (50%. S-character). Chical Centre This band will be the shortest because of sp-Hybridisation y Aldehyde o a - Alkyne Alleyne - -)C=0 Loud & co kéfone Aldehyde ketone us bog Thisl Group - SH~ This