12. Calculate the energy released, in kJ, when 1.00 mol U-238 isotopes (nuclear mass = 238.05078...

Question

Question

Answer 1

Answer #1

U^238 —-----------> Th^234 +He^4

92. 90. 2

238.05078. 234.03596. 4.002603

Mass defect = (238.05078)-(234.03596+4.002603)

=238.05078 - 238.038563

= 0.012217amu

Energy released =0.012217amux931Mev

=11.374Mev

But,1Mev= 1.602*10^-16KJ

For 11.374Mev =

11.374x1.602*10^-16

= 1.82*10^-15 KJ

Answer 2

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