Light of wavelength 700 nm is shown upon a double slit. The bright fringes are observed...
Light of wavelength 700 nm is shown upon a double slit. The bright fringes are observed to be 2.1 mm apart on the viewing screen. Find the fringe spacing if the light were changed to a wavelength of 450 nm.
Homework Answers
Distance between consecutive bright fringes S= wavelength*D/d
where D = distance of the screen
d = distance between slits
=> S proportional to wavelength
=> S2/S1 = wavelength2 /wavelength1
=> fringe spacing for wavelength = 450 nm is S2 = 450*2.1/700 = 1.35 mm
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