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1 - 2 Sketch the span of the columns of A= to Až = 7 and its span. ). On the same grid sketch a non-zero solution -8) 12 11

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Answer #1

Clearly, the columns of \mathbf{A} are

\begin{bmatrix} 1\\ 4 \end{bmatrix} and CON

which are linearly dependent as

\begin{bmatrix} -2\\ -8 \end{bmatrix} = -2\begin{bmatrix} 1\\ 4 \end{bmatrix}

Thus, the span of the columns of A can be plotted as

s + - | 10 x1 心-6

Now, consider a vector \vec{x} = \begin{bmatrix} x \\ y \end{bmatrix} that satisfies AT = 0 then,

I – 2y = 0 4.1 – 8y = 0

Clearly, the solutions of the equations correspond to all O, Y ER such that

I = 2y

This corresponds to the vectors of the form

=1

Thus we can plot the span of the solutions as

必6 -10 10

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