A transverse wave on a wire is given by D(x,t)=0.045sin(26x−ft) where D and x are in meters and t is in seconds. a) Find an expression for a wave with the same amplitude, wavelength, and frequency but traveling in the opposite direction. b)What is the speed of either wave?
A transverse wave on a wire is given by D(x,t)=0.045sin(26x−ft) where D and x are in...
A transverse wave on a wire is given by D(x, t) = 0.030 sin(27x - 567t) where x is in meters and t is in seconds. a) Determine an expression for a wave with the same amplitude, wavelength, and frequency but traveling in the opposite direction. b) What is the speed of either wave?
A transverse traveling wave on a cord is represented by D=0.43sin(5.4x+66t) where D and x are in meters and t is in seconds. A)Determine the wavelength of this wave. B)Determine the frequency of this wave. C)Determine the speed of this wave. D)Determine the direction of this wave. E)Determine the amplitude of this wave. F)Determine maximum and minimum speeds of particles of the cord.
A traveling wave is described by the function y(x,t) = 2 cos(3pi*t − 4pi*x), where y is in cm, x is in meters, and t is in seconds. a. In what direction is the wave traveling? b. What is the speed of the wave? c. What is the transverse acceleration of the wave at y = 0 and t = 1 second? d. Write an expression for the second harmonic of this wave (i.e., same speed, but twice the frequency).
The equation of a transverse wave traveling along a very long string is given by y = 6.1 sin(0.018πx + 3.1πt), where x and y are expressed in centimeters and t is in seconds. Determine the following values. (a) the amplitude cm (b) the wavelength cm (c) the frequency Hz (d) the speed cm/s (e) the direction of propagation of the wave +x−x +y−y (f) the maximum transverse speed of a particle in the string cm/s (g) the transverse displacement at...
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). Part A Find the amplitude. Part B Find the period Part C Find the frequency Part D Find the wavelength Part E Find the speed of propagation. Part F Is the wave traveling in the +x- or − x-direction?
The equation of a transverse wave traveling along a very long string is y = 3.96 sin(0.0444πx+ 7.89πt), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x = 1.05 cm when t = 0.843 s?
The equation of a transverse wave traveling along a very long string is y = 6.28 sin(0.0223πx+ 3.63πt), where x and yare expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x = 4.95 cm when t = 0.876 s?
6. A wave is described by y = 0.020 8 sin(kx - wt), where k = 2.22 rad/m, w = 3.66 rad/s, x and y are in meters, and t is in seconds. (a) Determine the amplitude of the wave. (b) Determine the wavelength of the wave. (c) Determine the frequency of the wave. (d) Determine the speed of the wave. 7. When a particular wire is vibrating with a frequency of 3.00 Hz, a transverse wave of wavelength 64.0 cm is produced. Determine the...
The transverse diaplacement for a wave on a string traveling in the +x direction is y(x,t) = (0.0090) sin (66.8m^-1)x-(310s^-1)t) what is it’s a) velocity b)wavelength c)frequency d)period e)amplitude (in units)
Chapter 16, Problem 010 The equation of a transverse wave traveling along a very long string is y 6.77 sin(0.0229x 4.31t), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) what is the transverse displacement at x = 2.50 cm when t...