Question

Water Level 275. A 1 meter wide cross section of a dam is shown Assume point B acts like a pin joint. Assume the dam rotates about point B and the soil reaction makes the triangular loading pattern shown Find X and X reactions at B and the value of the distributed load at C in N/m 2.40m Water Load 2400 N/m/-- Spil Load Weight of Dam wall 17000 Newtons Weight of Dam floor 9500 Newtons Apply the weights at the centroids of the wall and floor 1.32m

Answer 1

sigma m_b = 0 -1/2 times w_0 times 1.32 times 2/3 times 1.32 + 9500 times 0.66 + 1/2 times 2400 times 2.4 times 1/3 times 2.4 = 0 -0.5808 w_0 + 6270 + 2304 = 0 W_0 = 14762.4 n/M SIGMA f_Y = 0 By + 1/2 times 1472.4 times 1.32 = 0 By = -9743.184 N By = 9743.184 N(down arrow) sigma F_x = 0 Bx + 1/2 times 2400 times 2.4 = 0 B_x = -2880 N B_x = 2880 N (left arrow)