Question

estion 9 of 15 > A student holds a bike wheel and starts it spinning with an initial angular speed of 7.0 rotations per second. The wheel is subject to some friction, so it gradually slows down. In the 10.0 s period following the inital spin, the bike wheel undergoes 57.5 complete rotations. Assuming the frictional torque remains constant, how much more time Al, will it take the bike wheel to come to a complete stop? Ar = 0.1 The bike wheel has a mass of 0.725 kg and a radius of 0.385 m. If all the mass of the wheel is assumed to be located on the rim, find the magnitude of the frictional torque 14 that was acting on the spinning wheel ON 0.0107

Answer 1

son Wo= 7 rotation is = 7x2t rad's Let tofal t see is required to finally stopp W = wo tat o=7x27 tot first also give 0=5705*25 rad in 10 sec. ie o wot- O= wot + 1/2 x 72 [formu lah T= losec 57.5X2M =7+2T1 x 10-L & T xcog? 115 = 140 - 700 * 14T ho = 140-115= 25 to Zoo - 28 sec |--1. sz vad/s2 25 entra time need = 28-go = 18 sec

noo b) n=o.725, r=0.385m farctional Torque efer e la =m8²xx 2 = 0.725+ (0.38572. - Xpost Assume wheel as disie) = 0.084 nim Nom
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