a)
R = radius of the balloon
70 cm = 0.70 m
let the gaussian surface of radius , r1 = 54 cm = 0.54 m
Qenclosed = change enclosed by the gaussian surface = 0 (since all the charge is at surface of balloon at distance 70 cm )
Using gauss's law
E A = Qenclosed /
E A = 0
E = 0
b)
Electric field at any distance greater than or equal to radius of balloon is given as
E = k Q/r2
so E 1/r2
hence Esurface /E2 = r22/r12
25000/E2 = (191)2 /(70)2
E2 = 3.4 x 103 N/c
c)
at the surface electric field is given as
Es = k Q/R2
25000 = (9 x 109) Q/(0.70)2
Q = 1.4 x 10-6 C
A spherical balloon has a radius o R-70 cm, and its surface has been charged uniform...
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