Can you complete this program using same code please. DO not change any code. Thank you
In this problem you are given the root of a BST and you want to return the summation of all the values in the BST. Remember that the summation of a BST is the summation of all the nodes in the left subtree + the summation of all the nodes in the right subtree + the value of the current node
Expected behavior:
root = None root = insert_node(root, 50) root = insert_node(root, 25) root = insert_node(root, 70) root = insert_node(root, 90) root = insert_node(root, 30) root = insert_node(root, 60) root = insert_node(root, 10) print(sum_tree(root) == 335)
class TreeNode:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
def insert_node(cur_node, value):
if cur_node is None:
return TreeNode(value)
if value < cur_node.value:
cur_node.left = insert_node(cur_node.left, value)
else:
cur_node.right = insert_node(cur_node.right, value)
return cur_node
def sum_tree(cur_node):
# your code here
class TreeNode:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
def insert_node(cur_node, value):
if cur_node is None:
return TreeNode(value)
if value < cur_node.value:
cur_node.left =
insert_node(cur_node.left, value)
else:
cur_node.right =
insert_node(cur_node.right, value)
return cur_node
def sum_tree(cur_node):
if cur_node is None:
return 0
return cur_node.value + sum_tree(cur_node.left) +
sum_tree(cur_node.right)
root = None
root = insert_node(root, 50)
root = insert_node(root, 25)
root = insert_node(root, 70)
root = insert_node(root, 90)
root = insert_node(root, 30)
root = insert_node(root, 60)
root = insert_node(root, 10)
# print(sum_tree(root))
print(sum_tree(root) == 335)
Can you complete this program using same code please. DO not change any code. Thank you...
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