Complete the following table:
Signed two’s complement binary integers (where m=# of bits)
Using m bits |
Minimum Value that can be represented expressed in base 2 |
Minimum Value that can be represented expressed in base 10 |
Maximum Value that can be represented expressed in base 2 |
Maximum Value that can be represented expressed in base 10 |
7 |
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12 |
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15 |
Please check out the solution of the given problem... for any doubt, please let me know...
Thank you
The range formula for 2's complement is [ -2n-1 to +2n-1 -1 ] where n is the number of bits..
FOR 7 BIT:
The range of integers in 2's complement form in 7 bits is [ -27-1 to +27-1 - 1 ]
so minimum number can be represented is ( - 26 )10 => (-64)10 or (1111111)2
maximum number can be represented is ( + 26 - 1)10 => (+63 )10 or (0111111)2
FOR 12 BIT:
The range of integers in 2's complement form in 12 bits is [ -212-1 to +212-1 - 1 ]
so minimum number can be represented is ( - 211 )10 => ( - 2048 )10 or (111111111111)2
maximum number can be represented is ( + 211 - 1)10 => (+2047 )10 or (011111111111)2
FOR 15 BIT:
The rnge of integers in 2's complement form in 15 bits is [ -215-1 to +215-1 - 1 ]
so minimum number can be represented is ( - 214 )10 => ( - 16384)10 or (111111111111111)2
maximum number can be represented is ( + 214 - 1)10 => (+16383 )10 or (011111111111111)2
so the table will be...
Bits | Minimum Value that can be represented expressed in base 2 | Minimum Value that can be represented expressed in base 10 | Maximum Value that can be represented expressed in base 2 | Maximum Value that can be represented expressed in base 10 |
7 | (1111111)2 | (-64)10 | (0111111)2 | (+63 )10 |
12 | (111111111111)2 | ( - 2048 )10 | (011111111111)2 | (+2047 )10 |
15 | (111111111111111)2 | ( - 16384)10 | (011111111111111)2 | (+16383 )10 |
Complete the following table: Signed two’s complement binary integers (where m=# of bits) Using m bits...
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